巨炮开火时的强大冲击波!

这大家伙，甚是厉害！据说开炮时，能推着整个舰横着移动。

这么多的炮管挤在一起属巨炮吗？

好象以前兵器知识还是舰船知识有正面俯拍图，战列舰横向三炮齐射时，有舰体横移的痕迹

这是9炮齐射还是三炮齐射？

貌似这图有点老了吧

长缨贯苍穹 发表于 2014-12-5 16:09
气势的确牛逼哄哄
不过装药比补上FL-2
射程恐怕比直升机上扔下来的“企鹅”远不了几公里
碰着装c801这样的200t小艇搞不好也要跪
……
完美的诠释了什么叫做——
工夫再高，也怕菜刀
衣服再叼，一砖撂倒

这图好像是电影超级战舰里面的截图吧？应该是特效合成的，开炮的战列舰是密苏里号

衣阿华级，成了大炮巨舰的绝唱了

叼得飞起，巨舰大炮的震撼与美感，航母都比不上

这是1984年BB-61衣阿华在波多黎各别克斯岛附近海域用9门406mm舰炮与右舷6门127mm副炮射击

3484782 发表于 2014-12-5 17:38
这图好像是电影超级战舰里面的截图吧？应该是特效合成的，开炮的战列舰是密苏里号

这是1984年BB-61衣阿华在波多黎各别克斯岛附近海域用9门406mm舰炮与右舷6门127mm副炮射击

一条大琵琶呀~万均雷霆声呀~

stonewanglei24 发表于 2014-12-5 16:33
这是9炮齐射还是三炮齐射？

16楼的图好经典

好象以前兵器知识还是舰船知识有正面俯拍图，战列舰横向三炮齐射时，有舰体横移的痕迹
卑斯麦可侧移10米

屯骑校尉 发表于 2014-12-5 21:55
老掉牙的图了，密苏里号吧
你的头像亮了

又来横移10米，这种谬论还没完没了了。

3484782 发表于 2014-12-5 17:38
这图好像是电影超级战舰里面的截图吧？应该是特效合成的，开炮的战列舰是密苏里号
不是                        

不能少了这张

海盗对轰现代版。

为了抵消单侧后坐力

830005 发表于 2014-12-5 16:32
好象以前兵器知识还是舰船知识有正面俯拍图，战列舰横向三炮齐射时，有舰体横移的痕迹
齐射舰体横移20厘米左右。

这开火的声音对己方舰员的听力或者内脏 有没有什么副作用呀！还有 晚上突然一发，眼睛受得了不，毕竟隔i那么近！  

大炮时代的绝响。。

动不了那么多~~20厘米都没有~~况且火炮还有自己的液缓冲系统~~~军舰开炮移动10米就跟人中弹会飞一样可笑~~

wyczmj 发表于 2014-12-6 00:01
齐射舰体横移20厘米左右。

动不了那么多~~20厘米都没有~~况且火炮还有自己的液缓冲系统~~~军舰开炮移动10米就跟人中弹会飞一样可笑~~

蒸汽装甲舰 发表于 2014-12-5 22:54
又来横移10米，这种谬论还没完没了了。
什么时候都会有的~~前些时候战例舰吧还有转的计算数据~~实际横移小到不到1毫米~~可以忽略不计的~~然后有人就指着图片说就是移动了~~那么大浪~

曲奇 发表于 2014-12-6 00:34
动不了那么多~~20厘米都没有~~况且火炮还有自己的液缓冲系统~~~军舰开炮移动10米就跟人中弹会飞一样可 ...


看舰首浪花

又来了~~那是冲击波的浪花~~自己找视频看去~~~看动了么~

转自战例舰论坛~

能看的懂的人就看看不懂的我也懒得废话~特别是只看一张图片就拿来说事的

16寸炮开火时的总机械能
Given:
Projectile Weight （弹重）: Wp = 2,700 lbs.
Charge Weight（药包重）: Wc = 650 lbs.
Muzzle Velocity（炮口初速）: Vo = 2,500 fps.
Weight of Recoiling Parts（后座部件重）: Wr = 250,000 lbs.
g （重力加速度）= 32.174 fps^2
Projectile Kinetic Energy （弹丸动能）= 0.5*((Wp/g)/2)*Vo^2 = 2.622*10^8 ft-lb.
To compute the kinetic energy of the propellant gases we must know the average velocity of the gases as they escape the muzzle. Experiments have shown that this velocity varies between 1,200 and 1,400 mps. depending on the muzzle velocity of the weapon. For purposes of these calculations we will use 1,200 mps or 3,937 fps.
计算发射药燃气动能
Average outflow velocity of propellant gases（平均燃气喷射速度）: w = 3,937 fps
Gas Kinetic Energy（燃气动能） = 0.5*((Wc/g)/2)*w^2 = 78.29*10^6 ft-lb
To compute the Kinetic energy of the recoiling parts, we must determine the velocity that they would achieve if allowed to recoil with no retarding force. This is commonly referred to as the free recoil velocity. To account for the difference between the velocity of the projectile and that of the propellant gases, we will use the aftereffect coefficient B which is defined by the relationship:
计算后座部件动能
w = B*Vo, therefore B = 1.5748
Free Recoil Velocity（自由后座速度）: Vre = (((Wp/g)+B*(Wc/g))/(Wr/g))*Vo = 37.236 fps
Recoil Energy （后座能量）= ((Wr/g)/2)*Vre^2 = 5.387*10^6 ft-lb
The rotational energy of the projectile is small by comparison and can be neglected.
弹丸的旋转能量极小可以忽视。
The overall mechanical energy is only a part (40 to 50%) of the chemical energy of the propellant, since a considerable portion of the energy is carried off as heat by the propellant gases, or transmitted to the gun barrel.
总机械能只是发射药化学能的40%－50%，其余部分作为热能被燃气带走，或传递给炮管。
Ref. Rheinmetall Handbook on Weaponry, 1982, chapter 9.
Now, with these factors in mind, here are some additional calculations.
The momentum of a single projectile can be calculated as follows:
单一弹丸的动量
Projectile momentum （弹丸动量）= (Weight of projectile/g) * Muzzle velocity of projectile （弹丸重量/重力）×炮口初速
= (2,700 / 32.174) * 2,500
= 209.80 x 10^3
Momentum of the propellant gasses can be calculated from Leo's numbers as follows:
Propellant gas momentum （燃气动量）= (Wc/g) * w
= (650 / 32.174) * 3,937
= 79.54 x 10^3
Summing these:
两者的和：
Projectile momentum + Propellant gas momentum = 209.80 x 10^3 + 79.54 x 10^3
= 289.34 x 10^3
The Free Recoil momentum calculation can be used as a check, as it should be about equal to the sum of the momentums of the projectile and propellant gasses.
后座动量应该和弹丸加燃气的动量大致相等。
Free Recoil momentum = (Wr/g) * Vre
= (250,000 / 32.174) * 37.236
= 289.33 x 10^3
The Broadside Momentum for 9 projectiles can now be calculated as follows:
9发齐射的动量：
Broadside Momentum = 9 * (momentum of projectile + momentum of propellant gasses)
= 9 * (209.80 x 10^3 + 79.54 x 10^3)
= 2.60 x 10^6
Using Greg's formula, the velocity of an Iowa firing a 9-gun broadside can be recalculated as follows:
计算IOWA在齐射后的速度：
Mass of broadside * Velocity of broadside = Mass of ship * Velocity of ship
齐射质量×速度＝船质量×船速度
As the Mass of broadside * Velocity of broadside term is equivalent to Broadside Momentum, this formula can be restated as follows:
因为齐射质量×速度等于之前计算的齐射动量，推得：
Broadside Momentum = Mass of ship * Velocity of ship
齐射动量＝船质量×船速度（横移速度）
Solving for the velocity of the ship and using the above calculated momentum figures:
计算：
Velocity of ship （船横移速度）= Broadside Momentum / [Mass of ship] （齐射动量/船质量）
= 2.60 x 10^6 / [58,000 * (2,240 / 32.174)]
= 0.64 fps
So, the ship's velocity ON ICE with the guns firing at zero degrees elevation would be about 7.7 inches per second rather than the 6 inches per second calculated above. When one considers that any sideways motion of the ship through water is actually resisted by the wall created by the hull of the ship, whose wetted surface is about 860 feet long and 38 feet deep, then it can be easily understood that Dick Landgraff's comment above, "theoretically, a fraction of a millimeter," is closer to the truth.
结论：IOWA在冰面上以0角度齐射造成到船体横移速度为每秒7.7英寸。考虑到横移会被船体在水中部分阻挡，而船体的水线长度为860英尺，吃水38英尺，具体横移距离应该不到一毫米。

转自战例舰论坛~

能看的懂的人就看看不懂的我也懒得废话~特别是只看一张图片就拿来说事的

16寸炮开火时的总机械能
Given:
Projectile Weight （弹重）: Wp = 2,700 lbs.
Charge Weight（药包重）: Wc = 650 lbs.
Muzzle Velocity（炮口初速）: Vo = 2,500 fps.
Weight of Recoiling Parts（后座部件重）: Wr = 250,000 lbs.
g （重力加速度）= 32.174 fps^2
Projectile Kinetic Energy （弹丸动能）= 0.5*((Wp/g)/2)*Vo^2 = 2.622*10^8 ft-lb.
To compute the kinetic energy of the propellant gases we must know the average velocity of the gases as they escape the muzzle. Experiments have shown that this velocity varies between 1,200 and 1,400 mps. depending on the muzzle velocity of the weapon. For purposes of these calculations we will use 1,200 mps or 3,937 fps.
计算发射药燃气动能
Average outflow velocity of propellant gases（平均燃气喷射速度）: w = 3,937 fps
Gas Kinetic Energy（燃气动能） = 0.5*((Wc/g)/2)*w^2 = 78.29*10^6 ft-lb
To compute the Kinetic energy of the recoiling parts, we must determine the velocity that they would achieve if allowed to recoil with no retarding force. This is commonly referred to as the free recoil velocity. To account for the difference between the velocity of the projectile and that of the propellant gases, we will use the aftereffect coefficient B which is defined by the relationship:
计算后座部件动能
w = B*Vo, therefore B = 1.5748
Free Recoil Velocity（自由后座速度）: Vre = (((Wp/g)+B*(Wc/g))/(Wr/g))*Vo = 37.236 fps
Recoil Energy （后座能量）= ((Wr/g)/2)*Vre^2 = 5.387*10^6 ft-lb
The rotational energy of the projectile is small by comparison and can be neglected.
弹丸的旋转能量极小可以忽视。
The overall mechanical energy is only a part (40 to 50%) of the chemical energy of the propellant, since a considerable portion of the energy is carried off as heat by the propellant gases, or transmitted to the gun barrel.
总机械能只是发射药化学能的40%－50%，其余部分作为热能被燃气带走，或传递给炮管。
Ref. Rheinmetall Handbook on Weaponry, 1982, chapter 9.
Now, with these factors in mind, here are some additional calculations.
The momentum of a single projectile can be calculated as follows:
单一弹丸的动量
Projectile momentum （弹丸动量）= (Weight of projectile/g) * Muzzle velocity of projectile （弹丸重量/重力）×炮口初速
= (2,700 / 32.174) * 2,500
= 209.80 x 10^3
Momentum of the propellant gasses can be calculated from Leo's numbers as follows:
Propellant gas momentum （燃气动量）= (Wc/g) * w
= (650 / 32.174) * 3,937
= 79.54 x 10^3
Summing these:
两者的和：
Projectile momentum + Propellant gas momentum = 209.80 x 10^3 + 79.54 x 10^3
= 289.34 x 10^3
The Free Recoil momentum calculation can be used as a check, as it should be about equal to the sum of the momentums of the projectile and propellant gasses.
后座动量应该和弹丸加燃气的动量大致相等。
Free Recoil momentum = (Wr/g) * Vre
= (250,000 / 32.174) * 37.236
= 289.33 x 10^3
The Broadside Momentum for 9 projectiles can now be calculated as follows:
9发齐射的动量：
Broadside Momentum = 9 * (momentum of projectile + momentum of propellant gasses)
= 9 * (209.80 x 10^3 + 79.54 x 10^3)
= 2.60 x 10^6
Using Greg's formula, the velocity of an Iowa firing a 9-gun broadside can be recalculated as follows:
计算IOWA在齐射后的速度：
Mass of broadside * Velocity of broadside = Mass of ship * Velocity of ship
齐射质量×速度＝船质量×船速度
As the Mass of broadside * Velocity of broadside term is equivalent to Broadside Momentum, this formula can be restated as follows:
因为齐射质量×速度等于之前计算的齐射动量，推得：
Broadside Momentum = Mass of ship * Velocity of ship
齐射动量＝船质量×船速度（横移速度）
Solving for the velocity of the ship and using the above calculated momentum figures:
计算：
Velocity of ship （船横移速度）= Broadside Momentum / [Mass of ship] （齐射动量/船质量）
= 2.60 x 10^6 / [58,000 * (2,240 / 32.174)]
= 0.64 fps
So, the ship's velocity ON ICE with the guns firing at zero degrees elevation would be about 7.7 inches per second rather than the 6 inches per second calculated above. When one considers that any sideways motion of the ship through water is actually resisted by the wall created by the hull of the ship, whose wetted surface is about 860 feet long and 38 feet deep, then it can be easily understood that Dick Landgraff's comment above, "theoretically, a fraction of a millimeter," is closer to the truth.
结论：IOWA在冰面上以0角度齐射造成到船体横移速度为每秒7.7英寸。考虑到横移会被船体在水中部分阻挡，而船体的水线长度为860英尺，吃水38英尺，具体横移距离应该不到一毫米。

以后再有这类帖子我真是懒得看了~~

canyuyige 发表于 2014-12-5 16:16
这大家伙，甚是厉害！据说开炮时，能推着整个舰横着移动。
对于衣阿华这么打个头的船来说，俺脚着还不至于有较大的横向移动

就没人学过动量守恒吗？移动的根本就忽略不计。明显是水波纹而已。

要是说拿到现在做火力支援，406毫米口径过大。震动过大，机构也过于庞大。美国自己都开发了330毫米次口径弹药。似乎阿拉斯加级大型巡洋舰更合适，装备305毫米口径炮。

这玩意儿能穿透m1a2的主装甲么？

屯骑校尉 发表于 2014-12-5 22:16
呵呵，这妹子技术不错吧
看了，我喉咙不舒服，直干呕